#P1007. Series Summation——级数求和

Series Summation——级数求和

Statement

Given: Sn=1+12+13++1nS_n= 1+\dfrac{1}{2}+\dfrac{1}{3}+…+\dfrac{1}{n}. Obviously, for any integer kk, when nn is sufficiently large, Sn>kS_n>k.

Given an integer kk, find the smallest nn such that Sn>kS_n > k.

Input

A positive integer kk, where 1k151\le k \le 15.

Output

A positive integer nn.

Samples

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